Question

calculate oxidation number of Mn in K2MnO4??​

Answer 1

Answer:

There are 2 K+ ions which makes +2 and 4 O2- ions which makes -8 (4*-2) and in K2MnO2 we know the charge of the molecule is neutral so the overall oxidation number must be 0. Therefore +2 (K) + x (Mn) + -8 (O) = 0 which means x = +6 so the oxidation number of Mn is +6 in K2MnO4