Question

calculate oxidation underlined b4 of atom in the following a)Na2B4O7
​

Answer 1

Answer:

hello dear,

Explanation:

Explanation:

The oxidation number of a free element is always 0.

The oxidation number of a monatomic ion equals the charge of the ion.

The oxidation number of H is +1, but it is -1 in when combined with less electronegative elements.

The oxidation number of O in compounds is usually -2, but it is -1 in peroxides.

Answer 2

Explanation:

na²b407

2(-1)+x+7(-2)=0

-2+x-14=0

-2+x-14=0

-2-14+x=0

-16+x=0

x=16 OK friend