calculate p.d across each cell in the given figure solve this question plzzzz....
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Final Answer : A : 4 V : B, C = 2V
Steps:
1) By Observing the circuit,
Net EMF, = (3+3)-(3) = 3 V in Clockwise sense.
All resistors are in series, So
R(eq) = 1+1 +1 = 3 ohm
Net Current, I = V/R = 3V/3ohm = 1 A
2) We also observe that, Battery A acts as a load while Battery B & C acts as a Source :
Therefore,
Potential Difference across Battery A,
= E + IR =3 + 1*1 = 4 V
Potential Difference across Battery B, and C is
= E - IR = 3-1*1 = 2 V.
Hence, Potential Difference across batteries A, B, C are respectively 4V, 2 V & 2 V.
Steps:
1) By Observing the circuit,
Net EMF, = (3+3)-(3) = 3 V in Clockwise sense.
All resistors are in series, So
R(eq) = 1+1 +1 = 3 ohm
Net Current, I = V/R = 3V/3ohm = 1 A
2) We also observe that, Battery A acts as a load while Battery B & C acts as a Source :
Therefore,
Potential Difference across Battery A,
= E + IR =3 + 1*1 = 4 V
Potential Difference across Battery B, and C is
= E - IR = 3-1*1 = 2 V.
Hence, Potential Difference across batteries A, B, C are respectively 4V, 2 V & 2 V.
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