Question

If tanϴ= cot(60°+ϴ), find the value of ϴ.
(Class 10 Maths Sample Question Paper)

Answer 1

Given:
tanϴ= cot(60 °+ϴ)
cot(90 °- ϴ) = cot(60 °+ϴ)

[tanϴ= cot(90 ° - ϴ)]
90 °- ϴ = 60 °- ϴ)
ϴ +  ϴ = 90 ° - 60 °
2 ϴ = 30 °
ϴ = 30 ° / 2 = 15 °
ϴ = 15 °.
Hence, the value of ϴ is 15 °.

HOPE THIS WILL HELP YOU.

Answer 2

Hey there !!

Given that -

tan ∅ = cot ( 60 + ∅ )


=> cot ( 90 - ∅ ) = cot ( 60 +∅ )

[ ∵ tan∅. = cot ( 90 - ∅ ) ]

=> 90 - ∅ = 60 + ∅

=> 90 - 60 = ∅ + ∅

=> 2∅ = 30

=> ∅ = 15

Hence ∅ = 15

Hope this would help you !!