calculate percentage composition each of the elements ferric oxide
Answers
Answered by
3
Answer:
Ferric oxide Fourmula= Fe2O3
Relative molar mass= 112+48
= 160 g
Iron = 112÷160×100
= 70%
Oxygen= 48÷160×100
= 30%
Explanation:
Pls mark as brainliest. I'm ly 9th standard
Similar questions