Question

Calculate percentage composition of Ca3(PO4)2​

Answer 1

$Molecular \: formula \: of \: calcium \: phosphate \: is \:  Ca3(PO4)2.</p><p></p><p>$

$Its \: molar \: mass \: is 3(40)+2(31)+8(16)=310 g/mol.</p><p></p><p>$

$percent \: of \: calcium \: = \frac{120}{310} \times 100 = 38.70\%$

$percent \: of \: phosphorus</p><p></p><p> = \frac{62}{310} \times 100 = 20\% \:$

$percent \: of \: \: oxygen \: = \frac{128}{310} \times 100 = 41.29\%$