Question

Calculate percentage covalent character in HCl molecule having

bond length 100 pm and dipole moment. 1.2 debye

Answer 1

We know, μ=q×l

=1.6×10

−19

C×1.275(10

−10

)m

=2.04×10

−29

Cm

Actual μ of HCl = 1.03D = 1.03×3.336×10

−30

Cm

=0.34×10

−29

Cm

So percentage of ionic character =

Calculatedμ

Actualμ

×100

=

2.04×10

−29

0.34×10

−29

×100

=16.667% (approx)