Question

Calculate percentage of Na in Na3F6​

Answer 1

Answer:

37.70%

Explanation:

atomic mass of Na= 23

atomic mass of F= 19

molecular mass of Na3F6 = 183

%age of Na = 3×23×100/183

=37.70%

Answer 2

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Chemical compound : $\bf{Na_3F_6}$

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We have to find percentage composition of F in the given compound.

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For determining the % composition of element in a compound :

$\dag\:\boxed{\bf{\purple{Mass\:\%\:of\:an\:element=\dfrac{mass\:of\:that\:element\:in\:the\:compound\times 100}{molar\:mass\:of\:the\:compound}}}}$

Molar mass of compound :

Mw = 3(Na) + 6(F)

Mw = 3(23) + 6(19)

Mw = 69 + 114

Mw = 183g/mol

% composition of Na :

➝ %(Na) = n × w × 100/Mw

➝ %(Na) = 3 × 23 × 100/183

➝ %(Na) = 6900/183

➝ %(Na) = 37.7%