Calculate percentage of sulphur present in CuSo4.5h2O and show your working
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Answer:
13.06% Sulphur is there in the compound.
Explanation:
Atomic Mass of Copper = 64 u
Molecules of Copper = 1
Atomic Mass of Sulphur = 32 u
Molecules of Sulphur = 1
Atomic Mass of Oxygen = 16 u
Molecules of Oxygen = 9
Atomic Mass of Hydrogen = 1 u
Molecules of Hydrogen = 5
So,
Total Atomic Mass = (64*1)+(32*1)+(16*9)+(1*5) u
= 64+32+144+5 u
= 245 u
Percentage of Sulphur = (32/245)*100 %
= 13.06%
Hope this helps.
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