Question

Calculate ph of 0.05 ba(oh)2?

Answer 1

FOR Ba(OH)2 
Normality Is 2, So N=2M (molarity) 
For Ba(OH)2= 2*0.5= 1 . 
" For Solve Any question Always Use N" 

Now For A Basic Solution Question Gives Always pOH , Same For It.pOH= -log (OH) 
-log(10^-1) 
=1 
So pH iS 14-1= 13

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Answer 2

Answer:

FOR Ba(OH)2

Normality Is 2, So N=2M (molarity)

For Ba(OH)2= 2*0.5= 1 .

" For Solve Any question Always Use N"

Now For A Basic Solution Question Gives Always pOH , Same For It.pOH= -log (OH)

-log(10^-1)

=1

So pH iS 14-1= 13

here

is the answer

Explanation: