Calculate pH of 0.2m of NaoH
Answers
Explanation:
Concept: The acidity of the solution can be expressed in terms of pH . It is equal to the negative logarithm of hydrogen ion concentration in the solution. The expression for pH is as follows: The basicity of the solution can be expressed in terms of pOH. It is equal to the negative logarithm of hydroxide ion concentration in the solution. The expression for pOH is as follows: The relationship between pH and pOH at is, A strong base is defined as a substance that ionizes completely into its ions when dissolved in water. A weak base is defined as a substance that partially ionizes completely into its ions when dissolved in water Solution: Sodium hydroxide (NaOH) is a strong base. It completely ionizes in aqueous solution to give hydroxide ion and sodium ion. The ionization reaction of sodium hydroxide (NaOH) is as follows, Sodium hydroxide is a strong base and ionizes completely the concentration of hydroxide ions in the solution will be equal to the initial concentration of sodium hydroxide. Therefore pOH of NaOH can be calculated using the following relation: Here, is the concentration of hydroxide ion which is equal to the concentration of NaOH. Then using the relationship between pH and pOH , the pH of sodium hydroxide solution can be calculated by subtracting pOH value from 14. For example: Calculate pH of 0.2 M NaOH solution. The initial concentration of sodium hydroxide is 0.2 M. Therefore, the concentration of hydroxide ion in the solution is, Substitute the concentration of hydroxide ion in the formula for pOH. The pH of 0.2 M NaOH solutions is calculated as follows: Similar problems: Question: 1. How to calculate pH of KOH ? Solution: Potassium hydroxide (KOH) is a strong base. It completely ionizes in aqueous solution to give hydroxide ion and potassium ion. The ionization reaction of potassium hydroxide (KOH) is as follows, Potassium hydroxide is a strong base and ionizes completely the concentration of hydroxide ions in the solution will be equal to the initial concentration of potassium hydroxide. Therefore pOH of KOH can be calculated using the following relation: Here, is the concentration of hydroxide ion which is equal to the concentration of KOH. Then using the relationship between pH and pOH, the pH of potassium hydroxide solution can be calculated by subtracting pOH value from 14. Question: 2. How to calculate pH of ? Solution: Calcium hydroxide is a strong base. It completely ionizes in aqueous solution to give hydroxide ion and calcium ion. The ionization reaction of calcium hydroxide is as follows, Calcium hydroxide is a strong base and ionizes completely the concentration of hydroxide ions in the solution will be twice the initial concentration of calcium hydroxide because one mole of calcium hydroxide gives two moles of hydroxide ion upon ionization. Therefore pOH of can be calculated using the following relation: Here, is the concentration of hydroxide ion which is twice the concentration of . Then using the relationship between pH and pOH , the pH of calcium hydroxide solution can be calculated by subtracting pOH value from 14.
Answer: pH of 0.2m of NaOH.
(OH ^- )= 0.2 m = 2×10^-1 m
pOH=-log( OH^-)
= - log ( 2×10^-1)
= 0.03010
pH= 14- 0.03010
= 13.9699
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