Question

Calculate ph of the solution 0.002M HBr

Answer 1

Answer:

(c) 0.002M HBr,

dissociation of HBr is ... HBr\rightarrow H^++Br^-

concentration of H^+ = 0.002M

now, pH = -log(0.002) = -log(2 × 10^-3)

pH = 3 - log2 = 2.6987