Calculate positive and negative charge of 88 gram of CO2
Answers
The number of positive and negative charges present in the CO₂ molecule is 1.325×10²⁵
Given:
Weight of CO₂= 88grams
To Find:
The positive and negative charges of 88grams of CO₂
Solution:
We need to know the number of atoms present in 88grams of CO₂ molecule.
So we need to know the number of moles present in the 88grams of CO₂ molecule.
To calculate the number of moles(n) the formula is:
n = Given mass/ molar mass.
Given mass = 88grams
To calculate the molar mass of CO₂ molecule=(mass of carbon + mass of oxygen)
Mass of Carbon is = 12
Mass of Oxygen is = 16, as there are two oxygen molecules, = 2×16 = 32
The total mass = 16+32= 44grams.
So n = 88/44
= 2 moles.
The number of atoms is: the number of moles× Avogadro's number
= 2 × 6.023×10²³
= 12.046×10²³
Total electrons = carbon atomic number + oxygen atomic number
= 6+2(8)= 6+16=22
Positive and negative charges = total number of electrons × 6.023×10²³
= 22×6.023×10²³
=1.325×10²⁵
∴ There are 1.325×10²⁵ positive and negative charges present in 88 grams of CO₂ molecule.
There are 1.325×10²⁵ positive and negative charges present in 88 grams of CO₂ molecule.
Given:
Mass of CO₂ = 88grams.
To find:
Positive and negative charge on 88grams of CO₂.
Solution:
Number of moles(n) in 88grams of CO₂ = Given mass/ molar mass.
Given mass = 88grams
Molar mass of Carbon = 12
Molas mass of oxygen = 16
Since there are two oxygen molecules, = 2×16
= 32
Total molar mass= 16+32= 44grams.
n = 88/44
= 2 moles
The number of atoms is the same as the number of moles× Avogadro's number
= 2 × 6.023×10²³
= 12.046×10²³
Total electrons= 6+2(8)= 6+16=22
Positive and negative charges = total number of electrons × 6.023×10²³
= 22×6.023×10²³
=1.325×10²⁵
So, there are 1.325×10²⁵ positive and negative charges present in 88 grams of CO₂ molecule.
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