calculate possible angles between L vector and s vector for f electron
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- In physics, in particular quantum mechanics, the vector model of the atom is a model of the atom in terms of angular momentum.It can be considered as the extension of the Rutherford-Bohr-Sommerfeld atom model to multi-electron atoms.
- The model is a convenient representation of the angular momenta of the electrons in the atom. Angular momentum is always split into orbital L, spin S and total J:
- {\displaystyle \mathbf {J} =\mathbf {L} +\mathbf {S} .}
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Thus the angle between L and S vector of electron is θ = 106.78 º
Explanation:
- Orbital spin and total angular moments are denoted by L, S and J respectively. Let's suppose
- If L=2, S = 1, and J = 2,
- To find: the angle between L and S
- Now using vector atomic model of electron:
Solution:
J = L + S
J . J = |L|^2 + |S|^2 + 2|L|.|S| cosθ
So cosθ = [|J|^2 - |L|^2 - |S|^2] / [2|L|.|S| ]
Now |L| = ([L (L+1)]^1 / 2 ) ħ
|S| = ([S (S + 1)]^1/2 ) ħ
|J| = ([J (J + 1 )]^1/2 ) ħ
So cosθ = [J (J + 1) - L ( L + 1) - S (S + 1)] / [2 ([L (L + 1)]^1/2 ) × ([S (S + 1)]^1/2 ) ]
Now cosθ = 6 - 6 - 2 / 2 × (6 × 2)^1/2
cosθ = -0.2886
θ = 106.78º
Thus the angle between L and S vector of electron is θ = 106.78 º
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