if A(t,2t), B(-2,6)and C(3,1) are the Vertices of a triangle ABC and the area of triangle ABC is 5 cmsquare then find t
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5=1/2{t(6-1)+(-2)(1-2t)+3(2t-6)}=>
5*2={t(5)-2(1-2t)+3(2t-6)}=>
10={5t-2+4t+6t-18}=>
10={15t-20}=>
10+20=15t=>
30=15t
t=2
so, value of 't'=2
5*2={t(5)-2(1-2t)+3(2t-6)}=>
10={5t-2+4t+6t-18}=>
10={15t-20}=>
10+20=15t=>
30=15t
t=2
so, value of 't'=2
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