Question

Calculate pressure exerted by a cube of side 2 cm and mass 3 kg (g =10 m/sec^

Answer 1

Answer:

$\large\bold\red{Pressure = 7.5 \times {10}^{4} \:N{m}^{-2}}$

Explanation:

Given,

• A cube having side = 2 cm and mass = 3 Kg.

Now,

the force exerting by the cube on the surface is due to gravity.

And,

We know that,

• Force by gravity on a body of mass 'm' is given by mg, where g is acceleration due to gravity.

Therefore,

Force exerted by the cube = 3 × 10 = 30 N

And,

• The base of cube on the surface is a square having side length 2 cm or 0.02 m.

Therefore,

• The area of base $={(0.02)}^{2}=4\times{10}^{-4}\:{m}^{2}$

Now,

We know that,

• $\bold{Pressure,P= \frac{Force}{Area}}$

Therefore,

We get,

$= > p = \frac{30}{4 \times {10}^{ - 4} } \\ \\ = > p = \frac{3 \times 100 \times {10}^{3} }{4} \\ \\ = > p = 3 \times 25 \times {10}^{3} \\ \\ = >p = 75 \times {10}^{3} \\\\ = > p = 7.5 \times {10}^{4}$

Hence,

$\large\bold{Pressure = 7.5 \times {10}^{4} \:N{m}^{-2}}$

Answer 2

Explanation:

PRESURE=7.5×10^4 Nm

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