Question

calculate required amount of acetic acid In gram for preparing 250ml solutions of 2 mole​

Answer 1

Answer:

Number of moles of benzoic acid required =0.15 ×

1000

250

=0.0375 moles

Molar mass of benzoic acid =7(12)+6(1)+2(16)=84+6+32=122 g/mol

Mass of benzoic acid required =122×0.0375=4.575 g