Question

Calculate reynolds number for blood flowing at 30cm/s through an aorta of radius 1.0cm. Assume that the blood has a viscosity of 4m Pa & of a density of 1060 kg/m^3. What is the nature of flow.

Answer 1

Reynolds no.=
density× velocity×diameter÷viscosity
just find yourself

Answer 2

Answer:

The correct answer is 1590.

Explanation:

Given:

$V = 30 cm/s = 3*10^{-1} m/s$

$p = 1060 kg/m$

$d = 2x 1.0 cm = 20*10^{-2} m$

η = $4 m Pa s = 4*10^{-3} P a s = 4*10^{-3} Ns/m^{2}$

Formula:

$R_{e} = \frac{v p d }{n}$

= $(3*10^{-1} m/s) (1060 kg/m^{3} ) (2.0 *10^{-2} m) / (4 *10^{-3} Ns/m^{2} )$

= 1590

Therefore, the flow will be laminar because $R_{e}$ is less than 2000.

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