Calculate ∆S if one mole of ideal gas is heated from 27°C to 127°C at
a) constant volume
b) constant pressure
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Answer:
ΔS=Q/ΔT
For constant volume,ΔS=nCvΔT/ΔT=nCv=Cv
For constant pressure,ΔS=nCpΔT/ΔT=nCp=Cp
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Answer:Hey DUDE HERE Is UR ANSWER.
ΔS=Q/ΔT
a).For constant volume,ΔS=nCvΔT/ΔT=nCv=Cv
b) For constant pressure,ΔS=nCpΔT/ΔT=nCp=Cp
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