Question

Calculate Standard Gibbs Free Energy for
the given reaction : Zn + Cu2+ → Zn2+ + Cu.
Given E⁰cell = 1.10V​

Answer 1

Answer:

2.2123 KJ

Explanation:

∆G° = -n*F*E° cell. (F=96500 Cmol^-1)

= -2*96500*1.10

= -2.213 KJ