calculate the acceleration and distance of the body moving with sign metre per second square which comes to rest after travelling for 6 second
Harshitasood:
the question is not complete there must be intial velocity too
This is the question sry it’s not sign meter it’s 5 meter
ok
Answers
Answered by
1
u=5m/s
v= 0
t= 6sec
v=u+at
0= 5+A×6
-5=a×6
-5/6=a
-0.83=a
and the distance is
s=ut+1/2at^2
s=5×6+1/2×0.83×6^2
s=30+1/2×0.83×36
by cutting 2 with 36
s=30+0.83×18
s=44.94m
v= 0
t= 6sec
v=u+at
0= 5+A×6
-5=a×6
-5/6=a
-0.83=a
and the distance is
s=ut+1/2at^2
s=5×6+1/2×0.83×6^2
s=30+1/2×0.83×36
by cutting 2 with 36
s=30+0.83×18
s=44.94m
Are u sure
yes
Thanks
welcome
plz mark my amswer as brainliest.. if it helped u
How
Another dude answered
Total distance is 30 and acceleration is 5
Similar questions