Question

Calculate the acceleration of a body which starts from rest and travel 87.5m in 5sec​onds.​

Answer 1

Given

• A body which starts from rest and travels $\bf\red{87.5 m}$ in $\bf\green{5\: seconds}$

To Find

• $\bf\blue{Acceleration}$ of the body

Solution

$\large\star\:{\boxed{\sf{\purple{s = ut + \dfrac{1}{2}at^2 }}}}$

• $\large\sf\red{s} = displacement$
• $\large\sf\green{u} = initial\: velocity$
• $\large\sf\orange{t} = time\: taken$
• $\large\sf\blue{a} = acceleration$

$\longrightarrow\:\:\:\sf 87.5 = 0 \times 5 + \dfrac{1}{2} \times a \times {5}^{2}$

$\longrightarrow\:\:\:\sf 87.5 = 0 + \dfrac{ 1 }{2} \times a \times 5 \times 5$

$\longrightarrow\:\:\:\sf 87.5 = 0 + \dfrac{ 1 }{2} \times a \times 25$

$\longrightarrow\:\:\:\sf 87.5 \times 2 = 25a$

$\longrightarrow\:\:\:\sf \dfrac{87.5 \times 2}{25} = a$

$\longrightarrow\:\:\:\sf a = \dfrac{87.5 \times 2 }{25}$

$\longrightarrow\:\:\:\sf a = \dfrac{ 17.5 \times 2}{5}$

$\longrightarrow\:\:\:\sf a = \dfrac{35}{5}$

$\longrightarrow\:\:\:\bf\pink{a = 7 \; m/{s}^{2} }$

Hence,

• Acceleration of the body = $\bf\red{7 \; m/{s}^{2} }$

Answer 2

Explanation:

u=0

s 87.5m

t=5s

s=ut+1/2at^2

87.5=1/2a×25

a=87.5×2/25=7

.:a=7m/s^2