Question

Calculate the acceleration of a bus that speed up from 20ms-to 40ms-'in 8 seconds. -1​

Answer 1

Answer:

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Explanation:

2.5 ms^-2  

Explanation:

acceleration

= (final velocity - initial velocity)/time  

= [(40m/s) - (20m/s)]/8s  

= (20m/s)/8s  

= 5/2 m/s²  

= 2.5 m/s²

= 2.5 ms^-2

Answer 2

Given:

Initial velocity is 20 m/s.

Final velocity is 40 m/s.

Time taken is 8 sec .

To find:

Acceleration of bus ?

Calculation:

• Acceleration is a vector quantity characterized by the rate of change of velocity with respect to time.

• SI unit of acceleration is m/s².

$\therefore \: a = \dfrac{v - u}{t}$

$\implies \: a = \dfrac{40 - 20}{8}$

$\implies \: a = \dfrac{20}{8}$

$\implies \: a = 2.5 \: m/ {s}^{2}$

So, acceleration of objects is 2.5 m/s².