Question

calculate the acceleration of the car starting from rest which acquires a velocity of 60 m/s in 0.05h​

Answer 1

Solution:

Given,

• The car starting from rest
• Final Velocity = 60 m/s
• Initial velocity = 0 m/s. ( ∵ The body starts from rest )
• Time taken = 0.05 h = 180s

To find,

• Acceleration of car

_________________________________

Using the formula

a = v - u/t

Where

• a : acceleration
• v : final velocity
• t : time
• u : final velocity

→ a = 60 - 0/180

→ a = 60/180

→ a = 1/3

→ a = 0.33 m/s²

Hence , acceleration of car = 0.33 m/s²

Answer 2

Given:

Initial velocity of car,u= 0 m/s

Final velocity of car,v= 60 m/s

Time taken by car,t= 0.05h

To Find:

Acceleration of the car

Solution:

We know that,

• According to first equation of motion for constant acceleration,

$\purple{\underline{\boxed{\bf{v=u+at}}}}$

where,

v is final velocity

u is initial velocity

a is acceleration

t is time taken

$\rule{190}{1}$

It is given that,

$\longrightarrow\rm{t=0.05\ h=0.05\times3600\ s=180\ s}$

Let the acceleration of car be a

So, on applying first equation of motion on car, we get

$\longrightarrow\rm{v=u+at}$

$\longrightarrow\rm{60=0+a(180)}$

$\longrightarrow\rm{60=180a}$

$\longrightarrow\rm{180a=60}$

$\longrightarrow\rm{a=\dfrac{60}{180}}$

$\longrightarrow\rm\green{a=0.33\ m/s^{2}}$

Hence, the acceleration of car is 0.33 m/s².