Physics, asked by diyagoyal891gmailcom, 1 year ago

Calculate the acceleration of the system, tension in the string and thrust on the pulley in terms of g for the
situation shown in following diagram.

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Answers

Answered by SmritiSami
3

The value of acceleration of the system, tension in the string and thrust on the pulley in terms of g for the situation are g/3 m/s², 10g/3 N and √2×10g/3 N respectively.

Given:-

Mass of heavier body = 10kg

Mass of lighter body = 5kg

Tension in the rope = T

Acceleration of the system = a

To Find:-

The value of acceleration of the system, tension in the string and thrust on the pulley in terms of g for the situation.

Solution:-

We can easily calculate the The value of acceleration of the system, tension in the string and thrust on the pulley in terms of g for the situation by using these simple steps.

As

Mass of heavier body (m1) = 10kg

Mass of lighter body (m2) = 5kg

Tension in the rope = T

Acceleration of the system = a

According to the formula for lighter mass,

F(net) = m×a

i.e. (m×g) - T = m×a

5g - T = 5a

For heavier mass,

T - 0 = 10a

T = 10a

putting this value of T in above equation,

5g - 10a = 5a

5g = 5a + 10a

5g = 15a

a = 5g/15

a = g/3

Now, Tension in the string = T

T = 10a

T = 10 × g/3

T = 10g/3 N

Now, Thrust on the pulley = F

F² = T² + T²

F² = 2T²

on taking root both sides,

F = √2T

F = √2 × 10g/3 N

Hence, The value of acceleration of the system, tension in the string and thrust on the pulley in terms of g for the situation are g/3 m/, 10g/3 N and 2×10g/3 N respectively.

#SPJ1

Answered by sourasghotekar123
1

Answer:

Given information:

Mass of heavier body = 10kg

Mass of lighter body = 5kg

Tension in the rope = T

Acceleration of the system = a

To Locate:

The system's acceleration, string tension, and pulley thrust values, all expressed in terms of g.

Result:

By following these easy methods, we can quickly determine the system's acceleration, the string's tension, and the pulley's push in terms of g.

Mass of heavier body (m1) = 10kg

Mass of lighter body (m2) = 5kg

Tension in the rope = T

Acceleration of the system = a

According to the formula for lighter mass,

F(net) = m×a

i.e. (m×g) - T = m×a

5g - T = 5a

For heavier mass,

T - 0 = 10a

T = 10a

Putting this value of T in above equation,

5g - 10a = 5a

5g = 5a + 10a

5g = 15a

a = 5g/15

a = g/3

Now, Tension in the string = T

T = 10a

T = 10 × g/3

T = 10g/3 N

Now, Thrust on the pulley = F

F² = T² + T²

F² = 2T²

On taking root both sides,

F = √2T

F = √2 × 10g/3 N

As a result, the system's acceleration, string tension, and pulley thrust values for the circumstance are, respectively, g/3 m/s2, 10g/3 N, and 210g/3 N.

#SPJ2

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