Question

calculate the accleration due to gravity on surface of sattelight having a mass of 7.4×10^22 and radius of earth is 1.74×10^6m

Answer 1

I think by radius of earth you mean radius of satellite. We know F=GMm/r*r
mg=GMm/r*r
g=GM/r*r
now we put values in it.
M=7.4*10^22
G=6.67*10^(-11)
r=1.74*10^6
therefore g=1.63m/s^2

Answer 2

g = GM / r²
= [(6.67 × 10⁻¹¹ × 7.4 × 10²²) / (1.74 × 10⁶)²] m/s²
= 1.630 m/s²

∴ Acceleration due to gravity of that planet is 1.630 m/s²