Calculate the amonut of naoh required to neutralize 25 miliequivalents of hcl
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A Neutralization reaction occurs when a strong acid reacts with a strong base to produce water and a salt (ionic compound).
In our case, sulfuric acid (strong acid) will react with sodium hydroxide (strong base) to form water and sodium sulfate:
H 2 S O 4 + 2 N a O H → N a 2 S O 4 + 2 H 2 O
We start with the units that we want to end up with and we set that equal to our given value, which will be multiplied by a conversion factor (the molar ratio from the balanced chemical equation). The
98.08 g mol represents the molar mass of sulfuric acid and the 40.0 g m o l is the molar mass of sodium hydroxide.
So what we have is,
g2NaOH=25.0gH2SO4×1molH2SO4/98.08gH2SO4×2molNaOH/1molH2SO4×40.0gNaOH/1molNaOH=20.4gNaOH
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