Chemistry, asked by mohitkhanwale8288, 1 year ago

Calculate the amonut of naoh required to neutralize 25 miliequivalents of hcl

Answers

Answered by Wafabhatt
0

A Neutralization reaction occurs when a strong acid reacts with a strong base to produce water and a salt (ionic compound).

In our case, sulfuric acid (strong acid) will react with sodium hydroxide (strong base) to form water and sodium sulfate:

H 2 S O 4 + 2 N a O H → N a 2 S O 4 + 2 H 2 O

We start with the units that we want to end up with and we set that equal to our given value, which will be multiplied by a conversion factor (the molar ratio from the balanced chemical equation). The  

98.08 g mol  represents the molar mass of sulfuric acid and the  40.0 g m o l  is the molar mass of sodium hydroxide.

So what we have is,

g2NaOH=25.0gH2SO4×1molH2SO4/98.08gH2SO4×2molNaOH/1molH2SO4×40.0gNaOH/1molNaOH=20.4gNaOH

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