Calculate the amount (in grams) of KClO3 required to produce 1.8 mole of oxygen gas on its thermal decomposition. Calculate the amount (in grams) of KClO3 required to produce 1.8 mole of oxygen gas on its thermal decomposition
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Answer:
Decomposition of KClO
3
takes place as:
2KClO
3
(s)→2KCl(s)+3O
2
(g)
2 mole of KClO
3
=3 mole of O
2
∵ 3 mole O
2
formed by 2 mole KClO
3
∴2.4 mole of O
2
will be formed by:
(
3
2
×2.4) mol KClO
3
= 1.6 mole of KClO
3
.
Mass of KClO
3
= Number of moles × Molar mass
=1.6×122.5=196g
Answered by
0
Answer:
Decomposition of KClO
3
takes place as:
2KClO
3
(s)→2KCl(s)+3O
2
(g)
2 mole of KClO
3
=3 mole of O
2
∵ 3 mole O
2
formed by 2 mole KClO
3
∴2.4 mole of O
2
will be formed by:
(
3
2
×2.4) mol KClO
3
= 1.6 mole of KClO
3
.
Mass of KClO
3
= Number of moles × Molar mass
=1.6×122.5=196g
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