Calculate the amount of air inside a conical tent with base radius 7m and height 12m.
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Answered by
17
The amount of air inside the cone equals the volume of the cone
radius of the cone,r = 7m
height of the cone, h = 12m
Volume of cone = 1/3πr²h
=1/3×22/7×7××12 m³
=28×22 m³
=616 m³
Therefore, the amount of air inside the conical tent is 616 m³.
radius of the cone,r = 7m
height of the cone, h = 12m
Volume of cone = 1/3πr²h
=1/3×22/7×7××12 m³
=28×22 m³
=616 m³
Therefore, the amount of air inside the conical tent is 616 m³.
Answered by
2
the amount of air inside the conical tent=the vol.of the tent=1/3pi r^2 h
here,r=7
h=12
hence,the vol.= 1/3.pi.7².12=615.75216m³
here,r=7
h=12
hence,the vol.= 1/3.pi.7².12=615.75216m³
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