Calculate the amount of aluminium required to get 1120kg of iron in the reaction aluminum and iron oxide
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Here it is clear that , 2 moles of Aluminium produces 2 moles of iron metal.
so, no of moles of Aluminium = no of moles of iron
or, weight of Aluminium/atomic weight of Al = weight of iron/atomic weight of iron
or, weight of aluminium/27 = 1120/56
or, weight of aluminium = 1120 × 27/56 = 540 grams.
hence, 540g of aluminium required getting 1120g of iron by given reaction
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