Question

what volume of 0.2 N NaOH solution would be required to neutralize
completely 30mlof 0.5N HCL solution
​

Answer 1

75 mL is the correct answer

Step - by - step Explanation: NV = N'V' where each stands for,

• N = Normality (in N)
• V = Volume (in mL)

→ 0.2N × V = 0.5 N × 30 mL

→ 0.2 × V = 15

→ V = 15/0.2 or 150/2

→ V = 75 mL

Hence, 75 mL of NaOH ia required to neutralize 30 mL of HCl solution.

Answer 2

Answer:

Explanation:

75mlbis the answerds