Question

Calculate the amount of barium sulphate formed when 50 ML of BACL2 (20.8% w/v) and 100 ML solution of H2 SO4 (9.8% w/v) are mixed.

Answer 1

Answer:

11.56 g of BaSO4 will be formed.

Explanation:

Since, of the total 100 mL of 20.8% BaCl2 solution will be = 20.8 g BaCl2.

Again, the 50 mL of 9.8% H2SO4 solution will be = 4.9 g H2SO4 .

So, the equation which is BaCl2 + H2SO4 -> BaSO4 + 2HCl we get that.  

Mass of the BaCl2 is 208 g and of H2SO4 is 98 g.    

So, we get that the 98 g of H2SO4 will react with 208 g of the BaCl2.

Since, 1 g H2SO4 will react with 208/98 g BaCl2.

Hence, 4.9 g H2SO4 will be reacting with 10.4 g BaCl2.

Again, the 98 g H2SO4 will produce 233 g BaSO4.

So, the 1 g H2SO4 will produce 233/98 g BaSO4.

Hence, according to the question 4.9 g H2SO4 will give 11.65 g BaSO4.