calculate the amount of c02 liberated when 25 gram by heating 25 gram of caco3
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Answered by
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hola mate....here is your answer...
CaCO3 ----> CaO + CO2
1 mol of CaCO3 gives 1 mol of CO2.
then, 25 gm CaCO3, = 25/100 = 1/4 mols.
1/4 mols CaCO3 will give 1/4 mol of CO2
therefore , amount of CO2 A= 1/4 × 44 = 11/2 = 5.5 gm CO2
hope u understood ^_^
CaCO3 ----> CaO + CO2
1 mol of CaCO3 gives 1 mol of CO2.
then, 25 gm CaCO3, = 25/100 = 1/4 mols.
1/4 mols CaCO3 will give 1/4 mol of CO2
therefore , amount of CO2 A= 1/4 × 44 = 11/2 = 5.5 gm CO2
hope u understood ^_^
AdityaRocks1:
please follow me plz
^_^
Hey just telling you. 1/4 x 44 = 11g and not 5.5g
oh sry...........
still answer procedure is correct..... answer should be 11 gm ...
sry dear
its ok
Answered by
0
CaCO3 ----> CaO + CO2 1 mol of CaCO3 gives 1 mol of CO2. then, 25 gm CaCO3, = 25/100 = 1/4 mols. 1/4 mols CaCO3 will give 1/4 mol of CO2 therefore , amount of CO2 = 1/4 × 44 =
1/4 * 44 = 11
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