Question

calculate the amount of caco3 required to be heated in order to collect 1.135 litre of co2 at stp​

Answer 1

$\boxed{\Large{\red{\sf{\bold{CaCO_3 \xrightarrow{HEAT} CaO+CO_2}}}}}$

Now:-

We want to produce 1.135 L of Carbondioxide at STP

Number of Moles of CO2 will be :-

$moles=\dfrac{volume\:Given}{22.4}\\ \\ \\moles=\dfrac{1.135}{22.4}= 0.050669\\ \\ \\Moles \approx 0.051\:Moles$

$\rule{200}{2}$

Hence,

According to the Stoichiometric Coefficients we can say that:-

Moles of Calcium Carbonate=  Moles of Carbondioxide Produced.

$\rule{200}{2}$

Therefore:-

Moles of Calcium Carbonate that were initially taken was 0.051 Moles.

$\rule{200}{2}$

Molar mass of CaCO3 will be :-

$=40+12+48\\ \\ \\=40+60\\ \\ \\=100\:Grams$

$\rule{200}{2}$

Thus:

Amount of CaCO3 taken will be:-

$=0.051*100\\ \\ \\=5.1\:Grams$