VERIFY THAT THE EXTERIOR ANGLE IS EQUAL TO SUM OF INTERIOR OPPOSITE ANGLE
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Because an exterior angle is equal to the sum of the opposite interior angles, it follows that it must be larger than either one of them.An exterior angle of a triangle is always larger then either opposite interior angle.
Given: let angle PRS be an exterior angle of triangle PQR.
we have to prove that:angle PRS is equal to sum of angles PQR and QPR
(note:I am writing angle as this symbol )
verification : The sum of all angles of a triangle is 180 degree.
Therefore,PQR+QPR+PRQ=180 degree __(1)
PRQ+PRS=180 degree (linear pair)__(2)
From (1) & (2)
PQR+QPR+PRQ = PRQ+PRS
Therefore
PQR+QPR = PRS (Reason:eliminating PRQ from both sides)
(refer to the attach diagram then you will understand)
Hence, It is verified that THE EXTERIOR ANGLE IS EQUAL TO SUM OF INTERIOR OPPOSITE ANGLE
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