Question

Calculate the amount of charge flowing in 2 minutes in a wire of Resistance 10 when a potential difference of 20v is applied between its ends

Answer 1

Explanation:

R=10 ohm

V=20 V

V=iR

20=i*10

i=20/10

i=2 A

t=2 minutes (120 sec)

i=2 A

i=q/t

2=q/120

q=120*2

q= 240 C

Answer 2

answer:

  240 c

  the explanation:

  R = 10 ohm

  V = 20 V

  V = IR

  20 = I * 10

  I = 20/10

  i = 2a

  t = 2 minutes (120 seconds)

  i = 2a

  I = q / t

  2 = q / 120

  q = 120 * 2

  Q = 240 C