Question

Calculate the amount of energy associated with changing 20 g of
ice to water at 0 degrees Celsius.

Answer 1

Answer:

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Answer 2

Answer:

1600 calories OR 6694.4 joule

Explanation:

the amount of energy associated with changing m g of

ice to water at 0 degrees Celsius = m*L

WHERE, "L" is the latent heat of fusion of ice which is equal to 80 calories/g.

SO,

  amount of energy associated = m*L

                                                     = (20g)*(80 calories/g)

                                                     = 1600 calories

                                       OR        = 6694.4 joule       [ 1 kilo calories = 4184 joule]