Question

calculate the amount of energy released when radioactive undergoes fusion and results in a mass defect of 2kg.​

Answer 1

Answer:

mass defect(m)=2kg

speed of light in vacuum(c)=3×10^8 m/S

Energy released=mc^2=2×3×10^8 J

=6×10^8 Jmass defect(m)=2kg

speed of light in vacuum(c)=3×10^8 m/S

Energy released=mc^2=2×3×10^8 J

=6×10^8 J

Answer 2

Answer:

Mass defect in the reaction (m) = 2kg

Velocity of light (c) = 3×10^8ms^-1

By Einstein's equation,

Energy released E = mc^2

So E = 2×(3×10^8) ^2

= 1.8×10^7J

Explanation:

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