Question

calculate the amount of F.A.S required to prepare 1000mL of 0.1 M standard solution of F.A.S​

Answer 1

Answer:

Preparation and Standardization of 0.1 M Ferrous Ammonium...

Dissolve 40 g of ferrous ammonium sulfate in a previously cooled mixture of 40 ml of sulphuric acid and 200 ml of water.

Dilute with sufficient freshly boiled and cooled water to produce 1000 ml.

Standardize the solution in the following manner.

Explanation:

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Answer 2

Answer:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Molarity=\frac{n\times 1000}{V_s}Molarity=

V

s

n×1000

where,

Molarity = 0.1 M

n= moles of solute

V_sV

s

= volume of solution in ml = 1000 ml

Now put all the given values in the formula of molarity, we get

0.1=\frac{n\times 1000}{1000}0.1=

1000

n×1000

n = 0.1

moles of solute=\frac{\text {given mass}}{\text {molar mass}}=\frac{xg}{90g/mol}molesofsolute=

molar mass

given mass

=

90g/mol

xg

0.1=\frac{xg}{90g/mol}0.1=

90g/mol

xg

x=9gx=9g

Thus amount of oxalic acid required to prepare 1000 mL 0.1 M standard solution of oxalic acid is 9 grams

Explanation:

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