calculate the amount of glucose required to prepare 250g of 5% solution of glucose by mass
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molar mass of glucose=180gm/mol.given that 5%of 250g=12.5g solute.
then gm of solvent left=(given)250-12.5=237.5g of solvent.
Assuming the water is solvent amount of solute 12.5 +amount of solvent 237.5=250 g of glucose which is 5%solution of glucose by mass.
then gm of solvent left=(given)250-12.5=237.5g of solvent.
Assuming the water is solvent amount of solute 12.5 +amount of solvent 237.5=250 g of glucose which is 5%solution of glucose by mass.
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