Question

calculate the amount of Hcl required to prepare 100ml of 0.1m Hcl

Answer 1

Let no. of moles of HCl required be x.

volume = 0.1 litre

molarity = 0.1 M

molarity = (moles of solute)/(litres of solution)

0.1 = x/0.1

x=0.1 X 0.1 => x= 0.01 moles of HCl

Hence, 0.01 moles of HCl gas will be needed to make the solution.

1 mole of any gas at STP has volume of 22.4 litres.

So, 22.4 X 0.01 => 0.224 litres of HCl gas must be dissolved.

molar mass of HCl gas = 1 +35.5 => 36.5 grams per mole.

Hence, 36.5 X 0.01 =>  0.365 grams of HCl gas must be used.