Question

Calculate the amount of heat energy liberated when 18 g of steam at 100° C liquefies to form water at 100° C. Specific latent heat of vaporisation of steam is 2260 Jg$^{–1}$​

Answer 1

Solution:

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Here we have been asked to calculate the amount of heat energy liberated when 18 g of steam at 100°C liquefies to form water 100°C.

Specific latent heat of vaporisation of steam is 2260 Jg$^{–1}$.

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Some provided data in the question:

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• m = 18 g
• L = 2260 Jg$^{–1}$

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Where, m = Mass of steam condensed

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L = Specific heat of vaporisation of steam

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and H = Heat liberated by steam.

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So, heat liberated by steam (H) = mL

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= 2260 × 18

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= 40680 J.

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Thus. 40680 J is the solution.