calculate the amount of heat generated when 7200 coulombs is transferred in 1 hour through p.d of 5 volt
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Thanks for your question !
Let we see given,
Q = 7200
t = 1 hour i.e. 60 × 60 = 3600 s.
V = 5 V
We know that,
I = Q / t
= 7200 / 3600
= 2 A.
Now,
R = V / I
= 5 V / 2 A
= 2.5 Ω
H = I²Rt
= 2 × 2 × 2.5 × 3600
= 4 × 2.5 × 3600
= 10 × 3600
= 36000 J
= 36 KJ
The amount of heat generated when 7200 coulombs is transferred in 1 hour through potential difference of 5 volts is 36 kilo joules.
Let we see given,
Q = 7200
t = 1 hour i.e. 60 × 60 = 3600 s.
V = 5 V
We know that,
I = Q / t
= 7200 / 3600
= 2 A.
Now,
R = V / I
= 5 V / 2 A
= 2.5 Ω
H = I²Rt
= 2 × 2 × 2.5 × 3600
= 4 × 2.5 × 3600
= 10 × 3600
= 36000 J
= 36 KJ
The amount of heat generated when 7200 coulombs is transferred in 1 hour through potential difference of 5 volts is 36 kilo joules.
ArchitectSethRollins:
nice answer
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