Question

calculate the amount of heat in calories required to convert 5 grams of ice at zero degree celsius to steam at hundred degree Celsius mixture??

Answer 1

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һєяє' ʏȏȗя ѧṅśwєя ʟȏȏҡıṅɢ ғȏя________
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✯♦Let us see, how much quantity of heat is required.

♦Heat required to melt 5g of ice at 0°C to water at 0°C = 5g × 80 calorie per gram= 400 calorie.

♦Heat required to raise the temperature of 5g of water from 0°C to 100°C = 5g × 1calorie/g/1°C rise of temperature× 100°C= 500 calorie

♦Heat required to convert water at 100°C to steam at 100°C = 5g× 540calorie/g = 2700calorie.

♦Therefore total heat required = 400 calorie+500 calorie + 2700 calorie= 3600 calorie.
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Answer 2

The amount of heat required is $3600 cal$.

Definition of heat :

• The movement of kinetic energy from one media or item to another, or from an energy source to a medium or object, is referred to as heat.
• Radiation, conduction, and convection are three methods for transferring energy.

Solution -

$5g$ ice at zero to $5g$ water at zero.

$Q 1 =m*l_{f} =5*80=400 cal$

$5g$ ice at zero to $5g$ water at $100^{0} C$.

$Q 2 =ms ΔT=5*1*100=500 cal$

$5g$ water at $100^{0} C$ to $5g$ steam at $100^{0} C$,

$Q 3 =ml_{v} =5*540=2700 cal$

$Q=Q 1 +Q2 +Q 3=3600 cal$

Therefore, the amount of heat required is $3600 cal$.

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