Question

give full solution. it was urgent

Answer 1

Let x = 0.7Bar
⇒ x = 0.777..........  .........(1)
Multiplying (1) by 10 
⇒ 10x = 7.7...... = 7.777 ...........(2)
Subtracting (1) from (2)
⇒ 10x - x = 9x ⇒ 7.777 - 0.777 = 7    ⇒ 9x = 7 
⇒ x = 7/9
Let y = 0.47Bar
⇒ y = 0.4747 ..............  ........(1)
Multiplying (1) by 100 
⇒ 100y = 47.4747  ............(2)
Subtracting (1) from (2)
⇒ 100y - y = 99y
⇒ 47.4747 - 0.4747 = 47
⇒ 99y = 47
⇒ y = 47/99
Now,
0.7Bar = 7/9
and 0.47Bar = 47/99
0.6 = 6/10
6/10 + 7/9 + 47/99
Taking L.C.M. of the denominator and then solving it, we get.
⇒ (594 + 770 + 470)/990
⇒ 1834/990
⇒ 917/495
Hence, 0.6 + 0.7Bar + 0.47Bar = 917/495
........is your answer