Calculate the amount of heat required to convert 1Kg of ice at -10oC into steam at 100 oC at normal pressure. Specific heat of ice=2100J Kg-1K -1 . Latent heat of fusion of ice is 3.36x105J kg-1 . Specific heat capacity of water is4200 J Kg-1K -1 and latent heat of vaporization of water is 2.25x106 J kg-1
Answers
Answer:
all done it at some point, just coasting along with our life. We fall into the trap of doing the same routines day in and day out, maybe even year in and year out. Things in our life start to fall away as we just watch it happen; relationships, work, health. Then at some point, you realize you’ve stopped moving forward. You’ve come to a stop.
Instead of doing anything about it, though, we spend time dreaming about the things that could make our life better (or blaming the past for how we got here). So you end up waiting for something, anything to get you moving again. But it’ not going to come on its own, and that just slows you down more.
I’ve fallen into the trap myself recently. I was feeling stressed by my life, and when a living situation change was forced upon me, I saw it as a chance to take some action. I left my job and packed up my life to move home with my parents. I was hoping to find more clarity and inspiration by reconnecting with my family, who I’ve lived apart from for over 15 years.
But I learned the hard way, new life paths don’t just appear. I’ve spent the last two months spinning in a funk.
Answer:
We have the latent heat of fusion as 80 cal/g, specific heat of water as 1 cal/g/K and latent heat of vaporization as 540 cal/g.
Thus we get the amount of heat required as-
heat required to melt ice+heat required to raise the temperature of water from 0
o
C to 100
o
C + heat required ot vaporize water
=mL
ice
+mCΔT+mL
water
=(1×80)+(1×1×100)+(540×1)=720 cal