Question

Calculate the amount of heat required to convert 5g of ice of 0 degree celcius into water of 0degree celcius

Answer 1

Explanation:

Heat required to melt 5g of ice at 0°C to water at 0°C = 5g × 80 calorie per gram= 400 calorie. Heat required to convert water at 100°C to steam at 100°C = 5g× 540calorie/g = 2700calorie. Therefore total heat required = 400 calorie+500 calorie + 2700 calorie= 3600 calorie.

Answer 2

The amount of heat required is 1628.8 Joules.

Explanation:

The conversions involved in this process are :

$H_2O(s)(0^0C)\rightarrow H_2O(l)(0^0C)$

Now we have to calculate the enthalpy change.

$\Delta H=n\times \Delta H_{fusion}$

where,

$\Delta H$ = enthalpy change = ?

mass of ice = 5 g

n = number of moles of water = $\frac{\text{Mass of ice}}{\text{Molar mass of ice}}=\frac{5g}{18g/mole}=0.28mole$

$\Delta H_{fusion}$ = enthalpy change for fusion = 6010 J/mole

Now put all the given values in the above expression, we get

$\Delta H=0.28mole\times 6010J/mole=1628.8J$

Therefore, the amount of heat required is 1628.8 J

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