Question

calculate the amount of heat required to covert 2050 gram of ice into water??


~someone please answer fast.......​

Answer 1

Answer:

Given , L

ice

=3.34×10

5

J/kg,m=500g=0.5kg

From the definition of latent heat ,

Q=mL

or Q=0.5×3.34×10

5

=1.67×10

5

J