Question

Calculate the amount of heat required to raise the temperature of 500 gm of lead from

20 °C to 40 °C, given S.H.C of lead is 130 J kg-1

°C

-1

. [ convert 500 gm into S.I unit]​

Answer 1

the amount of heat required Q = m×s×∆t

Q = 0.5 × 130 × (40-20)

Q = 1300 joules or 1.3 kilo joules

Answer 2

Answer:

Don't know that much also diwansue gurung