Question

calculate the amount of lime present in 90 gm of caco3. ​

Answer 1

since, quicklime is CaO

CaCO3->CaO+CO2

Mole of caco3 in 90 gm:

90/100=0.9

1mole caco3=1mole of CaO

0.9mole caco3=0.9mole of CaO

0.9mole of CaO=0.9*56=50.4